What is the solution for (2dy)/(dx)+7y=1 ?

The solution for (2dy)/(dx)+7y=1 is y=-(e^{(-7x-c_{1})/2})/(7)+1/7

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(2dy)/(dx)+7y=1

\frac{2 d y}{d x} + 7 y = 1

y = - \frac{e ^{\frac{- 7 x - c _{1}}{2}}}{7} + \frac{1}{7}

Solution steps

\frac{2 d y}{d x} + 7 y = 1

Solve separable ODE:

y = - \frac{e ^{\frac{- 7 x - c _{1}}{2}}}{7} + \frac{1}{7}

y = - \frac{e ^{\frac{- 7 x - c _{1}}{2}}}{7} + \frac{1}{7}

\frac{1}{s - 3}

\frac{d}{d x} (\frac{ln ( x )}{2} - \frac{x ^{2}}{4})

\frac{\partial}{\partial x} (x, y)

n = 0 \sum \infty n! e^{- 2 n}

\frac{3 s + 1}{s ( s + 1 ) ( - s + 5 )}

What is the solution for (2dy)/(dx)+7y=1 ?
The solution for (2dy)/(dx)+7y=1 is y=-(e^{(-7x-c_{1})/2})/(7)+1/7