What is the sum from n=0 to infinity of 1/(n^2) ?

The sum from n=0 to infinity of 1/(n^2) is converges

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sum from n=0 to infinity of 1/(n^2)

n = 0 \sum \infty \frac{1}{n ^{2}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{2}}

Apply p-Series Test:

converges

= converges

\frac{\partial}{\partial x} (e^{6 x + 9 y})

y = \frac{1}{2} x, y = 1, y = \frac{1}{25} x^{2}

n = 5 \sum \infty sin (\frac{1}{n ^{2}})

\frac{d}{d x} (\frac{1}{2} cos (x))

\frac{d}{d x} (x ln (4 y) + x + y)

What is the sum from n=0 to infinity of 1/(n^2) ?
The sum from n=0 to infinity of 1/(n^2) is converges