What is the sum from n=5 to infinity of sin(1/(n^2)) ?

The sum from n=5 to infinity of sin(1/(n^2)) is converges

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sum from n=5 to infinity of sin(1/(n^2))

n = 5 \sum \infty sin (\frac{1}{n ^{2}})

converges

Solution steps

n = 5 \sum \infty sin (\frac{1}{n ^{2}})

Apply Series Comparison Test:

converges

= converges

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What is the sum from n=5 to infinity of sin(1/(n^2)) ?
The sum from n=5 to infinity of sin(1/(n^2)) is converges