What is the solution for (dy)/(dx)=e^{3x-2y} ?

The solution for (dy)/(dx)=e^{3x-2y} is y=(ln(2/3 e^{3x}+c_{1}))/2

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(dy)/(dx)=e^{3x-2y}

\frac{d y}{d x} = e^{3 x - 2 y}

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{3 x - 2 y}

Solve separable ODE:

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

n = 1 \sum \infty (\frac{10}{11})^{n}

\frac{\partial}{\partial x} (sin (2 x) cos (2 y))

d er i v a t i v e 3 e^{t}

\int - 6 tan^{2} (x) d x

x^{3} \frac{d y}{d x} + (2 - 3 x^{2}) y = x^{3}

What is the solution for (dy)/(dx)=e^{3x-2y} ?
The solution for (dy)/(dx)=e^{3x-2y} is y=(ln(2/3 e^{3x}+c_{1}))/2