What is (\partial)/(\partial x)(sin(2x)cos(2y)) ?

The answer to (\partial)/(\partial x)(sin(2x)cos(2y)) is cos(2y)cos(2x)*2

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(\partial)/(\partial x)(sin(2x)cos(2y))

\frac{\partial}{\partial x} (sin (2 x) cos (2 y))

cos (2 y) cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x) cos (2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (2 y) \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= cos (2 y) cos (2 x) \cdot 2

d er i v a t i v e 3 e^{t}

\int - 6 tan^{2} (x) d x

x^{3} \frac{d y}{d x} + (2 - 3 x^{2}) y = x^{3}

d er i v a t i v e ln (x e^{- 8 x})

\frac{d}{d x} (\frac{4 x}{4 + x})

What is (\partial)/(\partial x)(sin(2x)cos(2y)) ?
The answer to (\partial)/(\partial x)(sin(2x)cos(2y)) is cos(2y)cos(2x)*2