derivative of ln(2x^2-1)

Lösung

\frac{d}{d x} (ln (2 x^{2} - 1))

\frac{4 x}{2 x ^{2} - 1}

Schritte zur Lösung

\frac{d}{d x} (ln (2 x^{2} - 1))

Wende die Kettenregel an:

\frac{1}{2 x ^{2} - 1} \frac{d}{d x} (2 x^{2} - 1)

= \frac{1}{2 x ^{2} - 1} \frac{d}{d x} (2 x^{2} - 1)

\frac{d}{d x} (2 x^{2} - 1) = 4 x

= \frac{1}{2 x ^{2} - 1} \cdot 4 x

Vereinfache

\frac{1}{2 x ^{2} - 1} \cdot 4 x : \frac{4 x}{2 x ^{2} - 1}

= \frac{4 x}{2 x ^{2} - 1}

x \to - 0.00000001 lim (x^{x})

d er i v a t i v e f (x) = [x + (x + sin^{2} (x))^{3}]^{4}

d er i v a t i v e f (x) = x^{2} + 5 - 3 x^{- 2}

x \to \infty lim ((\frac{13 x}{13 x + 3})^{5 x})

\int \frac{2 x - 4}{( x ^{2} - 4 x + 7 ) ^{2}} d x