What is (\partial)/(\partial x)(xy-1) ?

The answer to (\partial)/(\partial x)(xy-1) is y

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(\partial)/(\partial x)(xy-1)

\frac{\partial}{\partial x} (x y - 1)

y

Solution steps

\frac{\partial}{\partial x} (x y - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (1) = 0

= y - 0

Simplify

= y

\frac{\partial}{\partial y} ((x^{2} - 1) (y + 2))

f (x) = \frac{3}{x ^{2}}, at x = 1

\int_{0}^{\frac{π}{4}} 4 sin^{2} (x) d x

h \to 0 lim ((1 + 5 h)^{\frac{1}{h}})

\frac{d}{d x} (y^{2} - x^{2})

What is (\partial)/(\partial x)(xy-1) ?
The answer to (\partial)/(\partial x)(xy-1) is y