What is the solution for y^'=(x^2+2*y^2)/(x*y) ?

The solution for y^'=(x^2+2*y^2)/(x*y) is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}

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y^'=(x^2+2y^2)/(xy)

y^{^{'}} = \frac{x ^{2} + 2 \cdot y ^{2}}{x \cdot y}

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

Solution steps

y^{'} (x) = \frac{x ^{2} + 2 \cdot y ^{2}}{x \cdot y}

Solve Bernoulli ODE:

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

\frac{d}{d x} (10 x sin (x))

9 x^{2} y^{2} + x^{\frac{3}{2}} y^{^{'}} = y^{2}

(x^{2} - 18) (2 x + 3)

\int x + \frac{1}{x ^{2}} d x

\frac{\partial}{\partial x} (x y - 1)

What is the solution for y^'=(x^2+2*y^2)/(x*y) ?
The solution for y^'=(x^2+2*y^2)/(x*y) is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}