What is the solution for (d^2-2)y=0 ?

The solution for (d^2-2)y=0 is y=c_{1}e^{sqrt(2)x}+c_{2}e^{-sqrt(2)x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(d^2-2)y=0

(d^{2} - 2) y = 0

y = c_{1} e^{2 x} + c_{2} e^{- 2 x}

Solution steps

(d^{2} - 2) y = 0

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x}

\frac{d ^{6} y}{d x ^{6}} - 2 \frac{d ^{3} y}{d x ^{3}} + y = 0

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = - 4, y^{^{'}} (0) = - 10

y^{^{''}} - y = 0, y (0) = 1, y (0) = 1

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = - 4, y^{^{'}} (0) = 3

x^{^{''}} + 4 x^{^{'}} - 5 x = 0

What is the solution for (d^2-2)y=0 ?
The solution for (d^2-2)y=0 is y=c_{1}e^{sqrt(2)x}+c_{2}e^{-sqrt(2)x}