What is the solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=-10 ?

The solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=-10 is y=-4e^{2t}-2e^{2t}t

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y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=-10

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = - 4, y^{^{'}} (0) = - 10

y = - 4 e^{2 t} - 2 e^{2 t} t

Solution steps

y^{''} (t) - 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = - 4 e^{2 t} - 2 e^{2 t} t

y = - 4 e^{2 t} - 2 e^{2 t} t

y^{^{''}} - y = 0, y (0) = 1, y (0) = 1

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = - 4, y^{^{'}} (0) = 3

x^{^{''}} + 4 x^{^{'}} - 5 x = 0

9 y^{^{''}} - 42 y^{^{'}} + 49 y = 0

x^{^{''}} + 2 a x^{^{'}} + b x = 0

What is the solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=-10 ?
The solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=-10 is y=-4e^{2t}-2e^{2t}t