What is the solution for y^{''}-8y^'-7y=0 ?

The solution for y^{''}-8y^'-7y=0 is y=c_{1}e^{(4+sqrt(23))t}+c_{2}e^{(4-sqrt(23))t}

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y^{''}-8y^'-7y=0

y^{^{''}} - 8 y^{^{'}} - 7 y = 0

y = c_{1} e^{(4 + 23) t} + c_{2} e^{(4 - 23) t}

Solution steps

y^{''} (t) - 8 y^{'} (t) - 7 y = 0

Solve linear ODE:

y = c_{1} e^{(4 + 23) t} + c_{2} e^{(4 - 23) t}

y = c_{1} e^{(4 + 23) t} + c_{2} e^{(4 - 23) t}

What is the solution for y^{''}-8y^'-7y=0 ?
The solution for y^{''}-8y^'-7y=0 is y=c_{1}e^{(4+sqrt(23))t}+c_{2}e^{(4-sqrt(23))t}