What is the solution for y^{''}+4y^'-5y=0,y(0)=-3,y^'(0)=21 ?

The solution for y^{''}+4y^'-5y=0,y(0)=-3,y^'(0)=21 is y=e^t-4e^{-5t}

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y^{''}+4y^'-5y=0,y(0)=-3,y^'(0)=21

y^{^{''}} + 4 y^{^{'}} - 5 y = 0, y (0) = - 3, y^{^{'}} (0) = 21

y = e^{t} - 4 e^{- 5 t}

Solution steps

y^{''} (t) + 4 y^{'} (t) - 5 y = 0

Solve linear ODE:

y = e^{t} - 4 e^{- 5 t}

y = e^{t} - 4 e^{- 5 t}

What is the solution for y^{''}+4y^'-5y=0,y(0)=-3,y^'(0)=21 ?
The solution for y^{''}+4y^'-5y=0,y(0)=-3,y^'(0)=21 is y=e^t-4e^{-5t}