What is the solution for 4y^{'''}+5y^{''}-23y^'-6y=0 ?

The solution for 4y^{'''}+5y^{''}-23y^'-6y=0 is y=c_{1}e^{2t}+c_{2}e^{-t/4}+c_{3}e^{-3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

4y^{'''}+5y^{''}-23y^'-6y=0

4 y^{^{'''}} + 5 y^{^{''}} - 23 y^{^{'}} - 6 y = 0

y = c_{1} e^{2 t} + c_{2} e^{- \frac{t}{4}} + c_{3} e^{- 3 t}

Solution steps

4 y^{'''} (t) + 5 y^{''} (t) - 23 y^{'} (t) - 6 y = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- \frac{t}{4}} + c_{3} e^{- 3 t}

y = c_{1} e^{2 t} + c_{2} e^{- \frac{t}{4}} + c_{3} e^{- 3 t}

What is the solution for 4y^{'''}+5y^{''}-23y^'-6y=0 ?
The solution for 4y^{'''}+5y^{''}-23y^'-6y=0 is y=c_{1}e^{2t}+c_{2}e^{-t/4}+c_{3}e^{-3t}