What is the solution for 2y-3y^{''}=0 ?

The solution for 2y-3y^{''}=0 is y=c_{1}e^{sqrt(2/3)t}+c_{2}e^{-sqrt(2/3)t}

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2y-3y^{''}=0

2 y - 3 y^{^{''}} = 0

y = c_{1} e^{\frac{2}{3} t} + c_{2} e^{- \frac{2}{3} t}

Solution steps

2 y - 3 y^{''} (t) = 0

Solve linear ODE:

y = c_{1} e^{\frac{2}{3} t} + c_{2} e^{- \frac{2}{3} t}

y = c_{1} e^{\frac{2}{3} t} + c_{2} e^{- \frac{2}{3} t}

What is the solution for 2y-3y^{''}=0 ?
The solution for 2y-3y^{''}=0 is y=c_{1}e^{sqrt(2/3)t}+c_{2}e^{-sqrt(2/3)t}