What is the solution for (D^3-4D^2+5D)y=0 ?

The solution for (D^3-4D^2+5D)y=0 is y=c_{1}+e^{2x}(c_{2}cos(x)+c_{3}sin(x))

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(D^3-4D^2+5D)y=0

(D^{3} - 4 D^{2} + 5 D) y = 0

y = c_{1} + e^{2 x} (c_{2} cos (x) + c_{3} sin (x))

Solution steps

(D^{3} - 4 D^{2} + 5 D) y = 0

Solve linear ODE:

y = c_{1} + e^{2 x} (c_{2} cos (x) + c_{3} sin (x))

y = c_{1} + e^{2 x} (c_{2} cos (x) + c_{3} sin (x))

What is the solution for (D^3-4D^2+5D)y=0 ?
The solution for (D^3-4D^2+5D)y=0 is y=c_{1}+e^{2x}(c_{2}cos(x)+c_{3}sin(x))