What is the solution for y^{''}-2y^'=0,y(0)=0,y^'(0)=-2 ?

The solution for y^{''}-2y^'=0,y(0)=0,y^'(0)=-2 is y=-e^{2t}+1

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y^{''}-2y^'=0,y(0)=0,y^'(0)=-2

y^{^{''}} - 2 y^{^{'}} = 0, y (0) = 0, y^{^{'}} (0) = - 2

y = - e^{2 t} + 1

Solution steps

y^{''} (t) - 2 y^{'} (t) = 0

Solve linear ODE:

y = - e^{2 t} + 1

y = - e^{2 t} + 1

What is the solution for y^{''}-2y^'=0,y(0)=0,y^'(0)=-2 ?
The solution for y^{''}-2y^'=0,y(0)=0,y^'(0)=-2 is y=-e^{2t}+1