What is the solution for x^{''}+0.5*x^'+17/16*x=0 ?

The solution for x^{''}+0.5*x^'+17/16*x=0 is x=e^{-0.25t}(c_{1}cos(t)+c_{2}sin(t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

x^{''}+0.5x^'+17/16x=0

x^{^{''}} + 0.5 \cdot x^{^{'}} + \frac{17}{16} \cdot x = 0

x = e^{- 0.25 t} (c_{1} cos (t) + c_{2} sin (t))

Solution steps

x^{''} (t) + 0.5 \cdot x^{'} (t) + \frac{17}{16} \cdot x = 0

Solve linear ODE:

x = e^{- 0.25 t} (c_{1} cos (t) + c_{2} sin (t))

x = e^{- 0.25 t} (c_{1} cos (t) + c_{2} sin (t))

What is the solution for x^{''}+0.5*x^'+17/16*x=0 ?
The solution for x^{''}+0.5*x^'+17/16*x=0 is x=e^{-0.25t}(c_{1}cos(t)+c_{2}sin(t))