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Beliebt Rechnen >

y^{''}-24y^'+αy=0,y(0)=1,y^'(0)=22

Lösung

y^{^{''}} - 24 y^{^{'}} + α y = 0, y (0) = 1, y^{^{'}} (0) = 22

Lösung

y = e^{t (12 + - α + 144)} (1 + \frac{- - α + 144 + 10}{2 144 - α}) - \frac{e ^{t (12 - - α + 144)} ( - - α + 144 + 10 )}{2 144 - α}

Schritte zur Lösung

y^{''} (t) - 24 y^{'} (t) + α y = 0

Solve linear ODE:

y = e^{t (12 + - α + 144)} (1 + \frac{- - α + 144 + 10}{2 144 - α}) - \frac{e ^{t (12 - - α + 144)} ( - - α + 144 + 10 )}{2 144 - α}

y = e^{t (12 + - α + 144)} (1 + \frac{- - α + 144 + 10}{2 144 - α}) - \frac{e ^{t (12 - - α + 144)} ( - - α + 144 + 10 )}{2 144 - α}

Graph

Beliebte Beispiele

6(d^2y)/(dx^2)-(dy)/(dx)-y=0

y^{'''}-y^{''}+4y^'+6y=0

2x^{''}+4x^'-3x=0

y^{''}+6y^'+13y=0,y(0)=1,y^'(0)=0