What is the solution for y^{''}+3y=0,y(0)= pi/8 ,y^'(0)=0 ?

The solution for y^{''}+3y=0,y(0)= pi/8 ,y^'(0)=0 is y= pi/8 cos(sqrt(3)t)

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y^{''}+3y=0,y(0)= pi/8 ,y^'(0)=0

y^{^{''}} + 3 y = 0, y (0) = \frac{π}{8}, y^{^{'}} (0) = 0

y = \frac{π}{8} cos (3 t)

Solution steps

y^{''} (t) + 3 y = 0

Solve linear ODE:

y = \frac{π}{8} cos (3 t)

y = \frac{π}{8} cos (3 t)

What is the solution for y^{''}+3y=0,y(0)= pi/8 ,y^'(0)=0 ?
The solution for y^{''}+3y=0,y(0)= pi/8 ,y^'(0)=0 is y= pi/8 cos(sqrt(3)t)