What is the solution for y^{''}+b*y=0,y(0)-9y^'(0)=0,y^'(9)=0 ?

The solution for y^{''}+b*y=0,y(0)-9y^'(0)=0,y^'(9)=0 is y=c_{1}cos(sqrt(b)t)+c_{2}sin(sqrt(b)t)

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y^{''}+b*y=0,y(0)-9y^'(0)=0,y^'(9)=0

y^{^{''}} + b \cdot y = 0, y (0) - 9 y^{^{'}} (0) = 0, y^{^{'}} (9) = 0

y = c_{1} cos (b t) + c_{2} sin (b t)

Solution steps

y^{''} (t) + b \cdot y = 0

Solve linear ODE:

y = c_{1} cos (b t) + c_{2} sin (b t)

y = c_{1} cos (b t) + c_{2} sin (b t)

What is the solution for y^{''}+b*y=0,y(0)-9y^'(0)=0,y^'(9)=0 ?
The solution for y^{''}+b*y=0,y(0)-9y^'(0)=0,y^'(9)=0 is y=c_{1}cos(sqrt(b)t)+c_{2}sin(sqrt(b)t)