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Beliebt Rechnen >

y^{''}-2y^'+2y=0,y(pi)=-1,y(0)=1

Lösung

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (π) = - 1, y (0) = 1

Lösung

y = e^{t} (\frac{1}{e ^{π}} cos (t) + c_{2} sin (t))

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = e^{t} (\frac{1}{e ^{π}} cos (t) + c_{2} sin (t))

y = e^{t} (\frac{1}{e ^{π}} cos (t) + c_{2} sin (t))

Graph

Beliebte Beispiele

y^{''}+6y^'+25y=0,y(0)=3,y^'(0)=7

4(d^2y)/(dx^2)-4(dy)/(dx)-3y=0

y^{''''}+2y^{'''}+37y^{''}+72y^'+36y=0

y^{'''}+3.2y^{''}+4.81y^'=0

y^{''}-16y=0,y(0)=4