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Beliebt Rechnen >

2y^{''}+4y^'+8y=0

Lösung

2 y^{^{''}} + 4 y^{^{'}} + 8 y = 0

Lösung

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t))

Schritte zur Lösung

2 y^{''} (t) + 4 y^{'} (t) + 8 y = 0

Solve linear ODE:

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t))

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t))

Graph

Beliebte Beispiele

2y^{''}-3y^'+1y=0

(4D^4-45D^2-70D-24)y=0

10(d^2y)/(dx^2)+20(dy)/(dx)+10y=0

y^{''}+4y^'+3y=0,y(0)=6,y^'(0)=2