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Beliebt Rechnen >

2yy^'+2=y^2+2x,y(0)=8

Lösung

2 y y^{^{'}} + 2 = y^{2} + 2 x, y (0) = 8

Lösung

y = - 2 x + 64 e^{x}

Schritte zur Lösung

2 y y^{'} (x) + 2 = y^{2} + 2 x

Solve Bernoulli ODE:

y = - 2 x + 64 e^{x}

y = - 2 x + 64 e^{x}

Graph

Beliebte Beispiele

derivative of xarcsec(x^3)

\frac{d}{d x} (x arcsec (x^{3}))

inverselaplace ((6+6s))/(2s^2+1)

in v erse l a pl a ce \frac{( 6 + 6 s )}{2 s ^{2} + 1}

derivative 9x^{1/2}

d er i v a t i v e 9 x^{\frac{1}{2}}

limit as x approaches 0 of ((sin(3x)))/x

x \to 0 lim (\frac{( sin ( 3 x ) )}{x})

x^2y^{''}-5xy^'+9y=0

x^{2} y^{^{''}} - 5 x y^{^{'}} + 9 y = 0