What is the solution for 6y^{''}+5y^'-6y=0 ?

The solution for 6y^{''}+5y^'-6y=0 is y=c_{1}e^{(2t)/3}+c_{2}e^{-(3t)/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

6y^{''}+5y^'-6y=0

6 y^{^{''}} + 5 y^{^{'}} - 6 y = 0

y = c_{1} e^{\frac{2 t}{3}} + c_{2} e^{- \frac{3 t}{2}}

Solution steps

6 y^{''} (t) + 5 y^{'} (t) - 6 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{2 t}{3}} + c_{2} e^{- \frac{3 t}{2}}

y = c_{1} e^{\frac{2 t}{3}} + c_{2} e^{- \frac{3 t}{2}}

What is the solution for 6y^{''}+5y^'-6y=0 ?
The solution for 6y^{''}+5y^'-6y=0 is y=c_{1}e^{(2t)/3}+c_{2}e^{-(3t)/2}