What is the solution for 9y^{''}-12y+4y=0 ?

The solution for 9y^{''}-12y+4y=0 is y=c_{1}e^{(2^{3/2}t)/3}+c_{2}e^{-(2^{3/2}t)/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

9y^{''}-12y+4y=0

9 y^{^{''}} - 12 y + 4 y = 0

y = c_{1} e^{\frac{2 ^{\frac{3}{2}} t}{3}} + c_{2} e^{- \frac{2 ^{\frac{3}{2}} t}{3}}

Solution steps

9 y^{''} (t) - 12 y + 4 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{2 ^{\frac{3}{2}} t}{3}} + c_{2} e^{- \frac{2 ^{\frac{3}{2}} t}{3}}

y = c_{1} e^{\frac{2 ^{\frac{3}{2}} t}{3}} + c_{2} e^{- \frac{2 ^{\frac{3}{2}} t}{3}}

What is the solution for 9y^{''}-12y+4y=0 ?
The solution for 9y^{''}-12y+4y=0 is y=c_{1}e^{(2^{3/2}t)/3}+c_{2}e^{-(2^{3/2}t)/3}