What is the solution for y^{''}+4y^'-21y=0,y(0)=1,y^'(0)=23 ?

The solution for y^{''}+4y^'-21y=0,y(0)=1,y^'(0)=23 is y=3e^{3t}-2e^{-7t}

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y^{''}+4y^'-21y=0,y(0)=1,y^'(0)=23

y^{^{''}} + 4 y^{^{'}} - 21 y = 0, y (0) = 1, y^{^{'}} (0) = 23

y = 3 e^{3 t} - 2 e^{- 7 t}

Solution steps

y^{''} (t) + 4 y^{'} (t) - 21 y = 0

Solve linear ODE:

y = 3 e^{3 t} - 2 e^{- 7 t}

y = 3 e^{3 t} - 2 e^{- 7 t}

What is the solution for y^{''}+4y^'-21y=0,y(0)=1,y^'(0)=23 ?
The solution for y^{''}+4y^'-21y=0,y(0)=1,y^'(0)=23 is y=3e^{3t}-2e^{-7t}