What is the solution for 4y^{''}-4y^'-3y=0,y(0)=1,y^'(0)=7 ?

The solution for 4y^{''}-4y^'-3y=0,y(0)=1,y^'(0)=7 is y=(1+11/4)e^{(3t)/2}-11/4 e^{-t/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

4y^{''}-4y^'-3y=0,y(0)=1,y^'(0)=7

4 y^{^{''}} - 4 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 7

y = (1 + \frac{11}{4}) e^{\frac{3 t}{2}} - \frac{11}{4} e^{- \frac{t}{2}}

Solution steps

4 y^{''} (t) - 4 y^{'} (t) - 3 y = 0

Solve linear ODE:

y = (1 + \frac{11}{4}) e^{\frac{3 t}{2}} - \frac{11}{4} e^{- \frac{t}{2}}

y = (1 + \frac{11}{4}) e^{\frac{3 t}{2}} - \frac{11}{4} e^{- \frac{t}{2}}

What is the solution for 4y^{''}-4y^'-3y=0,y(0)=1,y^'(0)=7 ?
The solution for 4y^{''}-4y^'-3y=0,y(0)=1,y^'(0)=7 is y=(1+11/4)e^{(3t)/2}-11/4 e^{-t/2}