What is the solution for x^{''}+100x^'+2470=0 ?

The solution for x^{''}+100x^'+2470=0 is x=c_{1}+c_{2}e^{-100t}-(247t)/(10)

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x^{''}+100x^'+2470=0

x^{^{''}} + 100 x^{^{'}} + 2470 = 0

x = c_{1} + c_{2} e^{- 100 t} - \frac{247 t}{10}

Solution steps

x^{''} (t) + 100 x^{'} (t) + 2470 = 0

Solve linear ODE:

x = c_{1} + c_{2} e^{- 100 t} - \frac{247 t}{10}

x = c_{1} + c_{2} e^{- 100 t} - \frac{247 t}{10}

What is the solution for x^{''}+100x^'+2470=0 ?
The solution for x^{''}+100x^'+2470=0 is x=c_{1}+c_{2}e^{-100t}-(247t)/(10)