What is the solution for y^{''}+7y^'+6y=e^{2x} ?

The solution for y^{''}+7y^'+6y=e^{2x} is y=c_{1}e^{-x}+c_{2}e^{-6x}+1/24 e^{2x}

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y^{''}+7y^'+6y=e^{2x}

y^{^{''}} + 7 y^{^{'}} + 6 y = e^{2 x}

y = c_{1} e^{- x} + c_{2} e^{- 6 x} + \frac{1}{24} e^{2 x}

Solution steps

y^{''} (x) + 7 y^{'} (x) + 6 y = e^{2 x}

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} e^{- 6 x} + \frac{1}{24} e^{2 x}

y = c_{1} e^{- x} + c_{2} e^{- 6 x} + \frac{1}{24} e^{2 x}

What is the solution for y^{''}+7y^'+6y=e^{2x} ?
The solution for y^{''}+7y^'+6y=e^{2x} is y=c_{1}e^{-x}+c_{2}e^{-6x}+1/24 e^{2x}