derivative of sqrt(1+sin(2x))

Lösung

\frac{d}{d x} (1 + sin (2 x))

\frac{cos ( 2 x )}{1 + sin ( 2 x )}

Schritte zur Lösung

\frac{d}{d x} (1 + sin (2 x))

Wende die Kettenregel an:

\frac{1}{2 1 + sin ( 2 x )} \frac{d}{d x} (1 + sin (2 x))

= \frac{1}{2 1 + sin ( 2 x )} \frac{d}{d x} (1 + sin (2 x))

\frac{d}{d x} (1 + sin (2 x)) = 2 cos (2 x)

= \frac{1}{2 1 + sin ( 2 x )} \cdot 2 cos (2 x)

Vereinfache

\frac{1}{2 1 + sin ( 2 x )} \cdot 2 cos (2 x) : \frac{cos ( 2 x )}{1 + sin ( 2 x )}

= \frac{cos ( 2 x )}{1 + sin ( 2 x )}

d er i v a t i v e ln (x + 1 + x^{2})

x \to \infty lim (\frac{25 6 ^{\frac{x}{2}}}{4 ^{2 x}})

\int \frac{6}{x ^{2} + 4} d x

\int (2 x + 3)^{5} d x

\frac{d}{d x} (\frac{7}{x + 9})