What is taylor x^3-3x^2+5x-7,0 ?

The answer to taylor x^3-3x^2+5x-7,0 is -7+5x-3x^2+x^3

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taylor x^3-3x^2+5x-7,0

taylor

x^{3} - 3 x^{2} + 5 x - 7, 0

- 7 + 5 x - 3 x^{2} + x^{3}

Solution steps

Apply the Taylor Formula

= - 7 + \frac{\frac{d}{d x} ( x ^{3} - 3 x ^{2} + 5 x - 7 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{3} - 3 x ^{2} + 5 x - 7 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{3} - 3 x ^{2} + 5 x - 7 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= - 7 + \frac{5}{1 !} x + \frac{- 6}{2 !} x^{2} + \frac{6}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= - 7 + 5 x - 3 x^{2} + x^{3}

(1.7) (3.3)

\int_{0}^{2} \frac{d t}{4 + t ^{2}} d x

y^{^{''}} + 49 y = 0, y (0) = 4, y^{^{'}} (0) = - 6

y^{^{'}} - y = 3 x - 3

f (x) = 1 - \frac{1}{x + 2}

What is taylor x^3-3x^2+5x-7,0 ?
The answer to taylor x^3-3x^2+5x-7,0 is -7+5x-3x^2+x^3