What is the derivative of f(x)=1-1/(x+2) ?

The derivative of f(x)=1-1/(x+2) is 1/((x+2)^2)

What is the first derivative of f(x)=1-1/(x+2) ?

The first derivative of f(x)=1-1/(x+2) is 1/((x+2)^2)

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derivative

\frac{1}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (1 - \frac{1}{x + 2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{1}{x + 2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{x + 2}) = - \frac{1}{( x + 2 ) ^{2}}

= 0 - (- \frac{1}{( x + 2 ) ^{2}})

Simplify

= \frac{1}{( x + 2 ) ^{2}}

What is the derivative of f(x)=1-1/(x+2) ?
The derivative of f(x)=1-1/(x+2) is 1/((x+2)^2)
What is the first derivative of f(x)=1-1/(x+2) ?
The first derivative of f(x)=1-1/(x+2) is 1/((x+2)^2)