What is the solution for y^{''}-y^'-2x=4x^2 ?

The solution for y^{''}-y^'-2x=4x^2 is y=c_{1}e^x+c_{2}-(4x^3)/3-5x^2-10x

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y^{''}-y^'-2x=4x^2

y^{^{''}} - y^{^{'}} - 2 x = 4 x^{2}

y = c_{1} e^{x} + c_{2} - \frac{4 x ^{3}}{3} - 5 x^{2} - 10 x

Solution steps

y^{''} (x) - y^{'} (x) - 2 x = 4 x^{2}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} - \frac{4 x ^{3}}{3} - 5 x^{2} - 10 x

y = c_{1} e^{x} + c_{2} - \frac{4 x ^{3}}{3} - 5 x^{2} - 10 x

What is the solution for y^{''}-y^'-2x=4x^2 ?
The solution for y^{''}-y^'-2x=4x^2 is y=c_{1}e^x+c_{2}-(4x^3)/3-5x^2-10x