Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}+4y=8e^{2t},y(0)=1,y^'(0)=-2(d^2y)/(dx^2)+2(dy)/(dx)=2x+5-e^{-2x}D(x)=(x-8)^2,S(x)=x^2+2x+28y^{''}+2y^'=x^2+1y^{''}-y^'-20y=27e^{-4c}
Frequently Asked Questions (FAQ)
What is the solution for y^{''}+0.01*(20-y)=0 ?
The solution for y^{''}+0.01*(20-y)=0 is y=c_{1}e^{t/(10)}+c_{2}e^{-t/(10)}+20