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Beliebt Rechnen >

y^{''}+2y^'=cos(4x)

Lösung

y^{^{''}} + 2 y^{^{'}} = cos (4 x)

Lösung

y = c_{1} + c_{2} e^{- 2 x} + \frac{1}{40} sin (4 x) - \frac{1}{20} cos (4 x)

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) = cos (4 x)

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 x} + \frac{1}{40} sin (4 x) - \frac{1}{20} cos (4 x)

y = c_{1} + c_{2} e^{- 2 x} + \frac{1}{40} sin (4 x) - \frac{1}{20} cos (4 x)

Graph

Beliebte Beispiele

2x^{''}+4x+20x=20\H(t)

2 x^{^{''}} + 4 x + 20 x = 20 H (t)

2y^{''}-y^'-y=25e^{-x}

2 y^{^{''}} - y^{^{'}} - y = 25 e^{- x}

(d^2y)/(dx^2)-2(dy)/(dx)+5y=e^xsin(2x)

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 5 y = e^{x} sin (2 x)

y^{''}+6y^'+45y=6

y^{^{''}} + 6 y^{^{'}} + 45 y = 6

2y^{''}+3y^'+5y=3cos(5t)

2 y^{^{''}} + 3 y^{^{'}} + 5 y = 3 cos (5 t)