What is the solution for y^{''}+9y=6cos(3x)+9sin(3x) ?

The solution for y^{''}+9y=6cos(3x)+9sin(3x) is y=c_{1}cos(3x)+c_{2}sin(3x)+xsin(3x)-(3xcos(3x))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+9y=6cos(3x)+9sin(3x)

y^{^{''}} + 9 y = 6 cos (3 x) + 9 sin (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + x sin (3 x) - \frac{3 x cos ( 3 x )}{2}

Solution steps

y^{''} (x) + 9 y = 6 cos (3 x) + 9 sin (3 x)

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + x sin (3 x) - \frac{3 x cos ( 3 x )}{2}

y = c_{1} cos (3 x) + c_{2} sin (3 x) + x sin (3 x) - \frac{3 x cos ( 3 x )}{2}

What is the solution for y^{''}+9y=6cos(3x)+9sin(3x) ?
The solution for y^{''}+9y=6cos(3x)+9sin(3x) is y=c_{1}cos(3x)+c_{2}sin(3x)+xsin(3x)-(3xcos(3x))/2