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Beliebt Rechnen >

y^{''}+y=sec^2(x),y(0)=2,y^'(0)=1

Lösung

y^{^{''}} + y = sec^{2} (x), y (0) = 2, y^{^{'}} (0) = 1

Lösung

y = 3 cos (x) + sin (x) - 1 + ln (sec (x) + tan (x)) sin (x)

Schritte zur Lösung

y^{''} (x) + y = sec^{2} (x)

Solve linear ODE:

y = 3 cos (x) + sin (x) - 1 + ln (sec (x) + tan (x)) sin (x)

y = 3 cos (x) + sin (x) - 1 + ln (sec (x) + tan (x)) sin (x)

Graph

Beliebte Beispiele

D (D - 3) y = 3 t + \frac{t}{2}

8y^{''}-6y^'+y=6cosh(x)

8 y^{^{''}} - 6 y^{^{'}} + y = 6 cosh (x)

y^{^{''}} - 100 y = 15

y^{'''}-y^{''}-y^'+y=7e^{-t}+6

y^{^{'''}} - y^{^{''}} - y^{^{'}} + y = 7 e^{- t} + 6

y^{''}-y^'-2y=2sin(x)

y^{^{''}} - y^{^{'}} - 2 y = 2 sin (x)