What is the solution for y^{''}+3y^'+2y=2,y(0)=3,y^'(0)=5 ?

The solution for y^{''}+3y^'+2y=2,y(0)=3,y^'(0)=5 is y=9e^{-t}-7e^{-2t}+1

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y^{''}+3y^'+2y=2,y(0)=3,y^'(0)=5

y^{^{''}} + 3 y^{^{'}} + 2 y = 2, y (0) = 3, y^{^{'}} (0) = 5

y = 9 e^{- t} - 7 e^{- 2 t} + 1

Solution steps

y^{''} (t) + 3 y^{'} (t) + 2 y = 2

Solve linear ODE:

y = 9 e^{- t} - 7 e^{- 2 t} + 1

y = 9 e^{- t} - 7 e^{- 2 t} + 1

What is the solution for y^{''}+3y^'+2y=2,y(0)=3,y^'(0)=5 ?
The solution for y^{''}+3y^'+2y=2,y(0)=3,y^'(0)=5 is y=9e^{-t}-7e^{-2t}+1