Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{'''}+8y^{''}+20y^'=x^2-4y^{''}-4y^'-21=0y^{''}+7y^'+6y=sin(2t),y(0)=1,y^'(0)=0y^{''}-y^'-2y=e^x-xy^{''}+y^'=e^t*cos(t)
Frequently Asked Questions (FAQ)
What is the solution for x^{''}-3x^'+2x=t ?
The solution for x^{''}-3x^'+2x=t is x=c_{1}e^{2t}+c_{2}e^t+t/2+3/4