2x^{''}+4x=6t

Lösung

2 x^{^{''}} + 4 x = 6 t

x = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{3 t}{2}

Schritte zur Lösung

2 x^{''} (t) + 4 x = 6 t

Solve linear ODE:

x = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{3 t}{2}

x = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{3 t}{2}

y^{^{''}} + 3 y^{^{'}} + 2 y = 18 + e x

y^{^{''}} + y^{^{'}} - 2 y = 2 x^{2} - 3 x

y^{^{''}} - 25 y = e^{5 t}

y^{^{''}} + 12 y = 7 e^{2 x}

y^{^{''}} - 10 y^{^{'}} + 25 y = 4 e^{5 x}