What is the solution for y^{''}+12y=7e^{2x} ?

The solution for y^{''}+12y=7e^{2x} is y=c_{1}cos(2sqrt(3)x)+c_{2}sin(2sqrt(3)x)+7/16 e^{2x}

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y^{''}+12y=7e^{2x}

y^{^{''}} + 12 y = 7 e^{2 x}

y = c_{1} cos (23 x) + c_{2} sin (23 x) + \frac{7}{16} e^{2 x}

Solution steps

y^{''} (x) + 12 y = 7 e^{2 x}

Solve linear ODE:

y = c_{1} cos (23 x) + c_{2} sin (23 x) + \frac{7}{16} e^{2 x}

y = c_{1} cos (23 x) + c_{2} sin (23 x) + \frac{7}{16} e^{2 x}

What is the solution for y^{''}+12y=7e^{2x} ?
The solution for y^{''}+12y=7e^{2x} is y=c_{1}cos(2sqrt(3)x)+c_{2}sin(2sqrt(3)x)+7/16 e^{2x}