What is the solution for y^{''}+y=sin(x),y(0)=0,y^'(0)=2 ?

The solution for y^{''}+y=sin(x),y(0)=0,y^'(0)=2 is y=-(xcos(x))/2+5/2 sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+y=sin(x),y(0)=0,y^'(0)=2

y^{^{''}} + y = sin (x), y (0) = 0, y^{^{'}} (0) = 2

y = - \frac{x cos ( x )}{2} + \frac{5}{2} sin (x)

Solution steps

y^{''} (x) + y = sin (x)

Solve linear ODE:

y = - \frac{x cos ( x )}{2} + \frac{5}{2} sin (x)

y = - \frac{x cos ( x )}{2} + \frac{5}{2} sin (x)

What is the solution for y^{''}+y=sin(x),y(0)=0,y^'(0)=2 ?
The solution for y^{''}+y=sin(x),y(0)=0,y^'(0)=2 is y=-(xcos(x))/2+5/2 sin(x)