What is the solution for y^{''}-2y^'-3y=e^{2x} ?

The solution for y^{''}-2y^'-3y=e^{2x} is y=c_{1}e^{3x}+c_{2}e^{-x}-1/3 e^{2x}

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y^{''}-2y^'-3y=e^{2x}

y^{^{''}} - 2 y^{^{'}} - 3 y = e^{2 x}

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{1}{3} e^{2 x}

Solution steps

y^{''} (x) - 2 y^{'} (x) - 3 y = e^{2 x}

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{1}{3} e^{2 x}

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{1}{3} e^{2 x}

What is the solution for y^{''}-2y^'-3y=e^{2x} ?
The solution for y^{''}-2y^'-3y=e^{2x} is y=c_{1}e^{3x}+c_{2}e^{-x}-1/3 e^{2x}