What is the solution for y^{''}+4y=3cos(x) ?

The solution for y^{''}+4y=3cos(x) is y=c_{1}cos(2x)+c_{2}sin(2x)+cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+4y=3cos(x)

y^{^{''}} + 4 y = 3 cos (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + cos (x)

Solution steps

y^{''} (x) + 4 y = 3 cos (x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + cos (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + cos (x)

What is the solution for y^{''}+4y=3cos(x) ?
The solution for y^{''}+4y=3cos(x) is y=c_{1}cos(2x)+c_{2}sin(2x)+cos(x)