What is the solution for y^{''}-9y=1,y(0)=0 ?

The solution for y^{''}-9y=1,y(0)=0 is y=(-c_{2}+1/9)e^{3t}+c_{2}e^{-3t}-1/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-9y=1,y(0)=0

y^{^{''}} - 9 y = 1, y (0) = 0

y = (- c_{2} + \frac{1}{9}) e^{3 t} + c_{2} e^{- 3 t} - \frac{1}{9}

Solution steps

y^{''} (t) - 9 y = 1

Solve linear ODE:

y = (- c_{2} + \frac{1}{9}) e^{3 t} + c_{2} e^{- 3 t} - \frac{1}{9}

y = (- c_{2} + \frac{1}{9}) e^{3 t} + c_{2} e^{- 3 t} - \frac{1}{9}

What is the solution for y^{''}-9y=1,y(0)=0 ?
The solution for y^{''}-9y=1,y(0)=0 is y=(-c_{2}+1/9)e^{3t}+c_{2}e^{-3t}-1/9