What is the first derivative of 3x+2 ?

The first derivative of 3x+2 is 3

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derivative of 3x+2

derivative of

3 x + 2

3

Solution steps

\frac{d}{d x} (3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 3 + 0

Simplify

= 3

\frac{2}{( s + 2 ) ( s + 1 )}

\int e^{8 x + e^{8 x}} d x

\frac{d}{d x} (x^{x} (ln (x) + 1))

\frac{\partial}{\partial y} (\frac{x + 2}{y + 2})

\frac{d}{d x} (x^{3} (x - 8)^{2})