What is the derivative of x^3(x-8^2) ?

The derivative of x^3(x-8^2) is 5x^4-64x^3+192x^2

What is the first derivative of x^3(x-8^2) ?

The first derivative of x^3(x-8^2) is 5x^4-64x^3+192x^2

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\frac{d}{d x} (x^{3} (x - 8)^{2})

5 x^{4} - 64 x^{3} + 192 x^{2}

Solution steps

\frac{d}{d x} (x^{3} (x - 8)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = (x - 8)^{2}

= \frac{d}{d x} (x^{3}) (x - 8)^{2} + \frac{d}{d x} ((x - 8)^{2}) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} ((x - 8)^{2}) = 2 (x - 8)

= 3 x^{2} (x - 8)^{2} + 2 (x - 8) x^{3}

Simplify

3 x^{2} (x - 8)^{2} + 2 (x - 8) x^{3} : 5 x^{4} - 64 x^{3} + 192 x^{2}

= 5 x^{4} - 64 x^{3} + 192 x^{2}

\frac{d}{d x} (\frac{1}{x - y})

\frac{d y}{d x} + \frac{1}{x} y = 0

\int 2 cos (\frac{x}{3}) d x

f (x) = x^{2} - 6 x - 7

x y^{2} y^{^{'}} = y^{3} - 5 x^{3}

What is the derivative of x^3(x-8^2) ?
The derivative of x^3(x-8^2) is 5x^4-64x^3+192x^2
What is the first derivative of x^3(x-8^2) ?
The first derivative of x^3(x-8^2) is 5x^4-64x^3+192x^2