integral from 0 to 1 of |2x-1|

Lösung

\int_{0}^{1} ∣ 2 x - 1 ∣ d x

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{0}^{1} ∣ 2 x - 1 ∣ d x

Entferne die Extremwerte

= \int_{0}^{\frac{1}{2}} - 2 x + 1 d x + \int_{\frac{1}{2}}^{1} 2 x - 1 d x

\int_{0}^{\frac{1}{2}} - 2 x + 1 d x = \frac{1}{4}

\int_{\frac{1}{2}}^{1} 2 x - 1 d x = \frac{1}{4}

= \frac{1}{4} + \frac{1}{4}

Vereinfache

\frac{1}{4} + \frac{1}{4} : \frac{1}{2}

= \frac{1}{2}

\int_{0}^{2 π} cos (3 t) e^{- 2 t} d t

y^{^{''}} - 2 y^{^{'}} + 82 y = 0

x \to 0 + lim ((1 + x)^{x})

x \to 0 + lim (tan (5 x) ln (8 x))

a re a y = 4 x^{2}, y = 234