What is the solution for y^'=-x/((y-3)) ?

The solution for y^'=-x/((y-3)) is y=3+sqrt(-x^2+c_{1)+9},y=3-sqrt(-x^2+c_{1)+9}

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y^'=-x/((y-3))

y^{^{'}} = - \frac{x}{( y - 3 )}

y = 3 + - x^{2} + c_{1} + 9, y = 3 - - x^{2} + c_{1} + 9

Solution steps

y^{'} (x) = - \frac{x}{( y - 3 )}

Solve separable ODE:

y = 3 + - x^{2} + c_{1} + 9, y = 3 - - x^{2} + c_{1} + 9

y = 3 + - x^{2} + c_{1} + 9, y = 3 - - x^{2} + c_{1} + 9

What is the solution for y^'=-x/((y-3)) ?
The solution for y^'=-x/((y-3)) is y=3+sqrt(-x^2+c_{1)+9},y=3-sqrt(-x^2+c_{1)+9}