What is the (dy)/(dx)=(x^2)/(1+y^2),y(2)=1 ?

The (dy)/(dx)=(x^2)/(1+y^2),y(2)=1 is (x^2)/2

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(dy)/(dx)=(x^2)/(1+y^2),y(2)=1

\frac{d y}{d x} = \frac{x ^{2}}{1 + y ^{2}}, y (2) = 1

\frac{x ^{2}}{2}

Solution steps

\frac{x ^{2}}{1 + y ^{2}} = \frac{x ^{2}}{1 + y ^{2}}

Constant function results in a constant

y (2) = 1

= \frac{x ^{2}}{1 + 1 ^{2}}

Simplify

\frac{x ^{2}}{1 + 1 ^{2}} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

What is the (dy)/(dx)=(x^2)/(1+y^2),y(2)=1 ?
The (dy)/(dx)=(x^2)/(1+y^2),y(2)=1 is (x^2)/2